This simulates filling a form on a website, and submitting it. You cant set content-type to documentJson, because non-file fields must not have a Content-Type header, see HTML 5 spec 4.10.21.8 multipart form data. postman1.form-dataform-data&,2.x-www-form-urlencodeform-datax-www-form-urlencode Website forms often send data to APIs as multipart/form-data. Each key-value pair is sent a block of data with a boundary delimiting each part. -d, --data, --data-ascii,--data-binary, --data-raw Copy Request As cURL Sometimes you may want to get the curl format of an http request quickly and save it to clipboard, just pressing F1 and then selecting/typing Rest Client: Copy Request As cURL or simply right-click in the editor, and select Copy Request As cURL . The body editor is divided into 4 areas and has different controls depending on the body type. 1) If you have to send Content-Type: multipart/form-data OR simply form-data. You can think of x-www-form-urlencoded as .txt file and form-data as .html file. I am using postman and making an api post request where I am adding body with x-www-form-urlencoded key/values and it works fine in postman. After configuring all the things click on send and see out put like this -- see image. 3Json. form-data is a fancier way of encoding data than x-www-form-urlencoded. You can use both of them. Angular tries to automatically set http header content-type according to request body, so there is absolutely no need to set it manually. In other words Request Part parse your json string object from request to your class object. 2form data. form-data. Related. Library postman-to-openapi is able to parse the Postman collection body request of type form-data, as Postman only support the parameter types Text and File (as you can see in next image) this are the only supported types for the Library. postmanform-datapost Generating Multipart form data body from text for RestSharp request. In computing, POST is a request method supported by HTTP used by the World Wide Web.By design, the POST request method requests that a web server accept the data enclosed in the body of the request message, most likely for storing it. Multipart Multipart: 2. multipart/form-data You will put your route and use form-data and post the value and image,document.in postman. multipart/form-data rfc2388 HTTP POST 1995ietf rfc1867RFC 1867 -Form-based File Upload in HTML multipart/form-data is the default encoding a web form uses to transfer data. In the end of day they both deliver some http payload. The "multipart" boundary delimiters and header fields are always represented as 7bit US-ASCII in any case (though the header fields may encode non-US-ASCII header text as per RFC 2047) and data within the body parts can be encoded on a part-by-part basis, with Content-Transfer-Encoding fields for each appropriate body part. Try getd.io playground links below to see what the headers and body look like: Send a request with x-www-form-urlencoded Form data allows you to send key-value pairs, and specify the content type. @RequestPart: This annotation associates a part of a multipart request with the method argument, which is useful for sending complex multi-attribute data as payload, e.g., JSON or XML.. The form-data editor lets you set key/value pairs (using the key-value editor) for your data. 0. I am not very experienced in developing using ReST and I have been trying to upload a file using HttpClient and multipart form. If you have to collect only one key/value pair of your posted form-data [HttpPost] [Route("api/test")] public HttpResponseMessage TestMethod(HttpRequestMessage request) { var testValue = multipart/form-data. You can attach files using form data. On the other hand, Request Param just obtain the string This is the first tab of Postman. In contrast, the HTTP GET request method retrieves And there`s two way to achieve your goals: JSON.stringify your data, and decode it in the back-end like this answer below; pass a file-like object and set Content-Type like this answer below 1) `multipart/form-data`2) `multipart/byteranges` 1. PostMappingStringFile 415 Content type 'multipart/form-data;boundary=-----9107Content-Type@RequestBody @Param @RequestParam@RequestBodyfile form-datajson Postman will automatically add the Content-Type header and will set it to multipart/form-data. In postman, set method type to POST.. Then select Body -> form-data -> Enter your parameter name (file according to your code)On the right side of the Key field, while hovering your mouse over it, there is a dropdown menu to select between Text/File.Select File, then a "Select Files" button will appear in the Value field. You can replicate this in Postman using the form-data Body tab. postmanpost4URLbody body 1x-www-from-urlencoded. That change most probably happens in interceptors. If the content-type header is application/json in browser's devtools that means request body has been changed till angular's attempt to define the header. It is often used when uploading a file or when submitting a completed web form.. Step 7- Run the application and use Postman to test Web API.If you are not aware about Postman, click here, otherwise see in the image how to configure Postman to test Web API. How to use OAuth2 in RestSharp using grant_type password. So if you